sql – 如何计算一对多关系
发布时间:2020-12-31 13:45:01 所属栏目:MsSql教程 来源:网络整理
导读:ReporterTbl与AttachmentTbl有一对多的关系. 在ReporterTbl中,我有一个ID(101),我可以使用AttachmentTbl多个与ReporterTbl.Id相关的附件 SELECT ISNULL(ReporterTbl.Id,0) AS Id,CONVERT(char(10),ReporterTbl.StartDate,101) AS StartDate,ISNULL(ReporterTb
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ReporterTbl与AttachmentTbl有一对多的关系. 在ReporterTbl中,我有一个ID(101),我可以使用AttachmentTbl多个与ReporterTbl.Id相关的附件 SELECT ISNULL(ReporterTbl.Id,0) AS Id,CONVERT(char(10),ReporterTbl.StartDate,101) AS StartDate,ISNULL(ReporterTbl.PriorityId,0) AS PriorityId,ISNULL(dbo.ReporterTbl.PriorityDesc,'') AS PriorityDesc,(select ReporterTbl.Id,COUNT(dbo.AttachmentTbl.Id) AS attachment_Id FROM dbo.AttachmentTbl RIGHT OUTER JOIN ReporterTbl ON dbo.AttachmentTbl.Id = ReporterTbl.Id GROUP BY ReporterTbl.Id) AS IsAttachment ) 基本上,我想知道的是ReporterTbl.ID,我有多少个附件? 表结构: ReporterTbl
Id int {**PrimaryKey**}
StartDate datetime
PriorityId int
PriorityDesc varchar(500
AttachmentTbl:
AttachmentId indentity
Id {**FK to ReproterTbl**}
Filename
Content
...
解决方法select r.id,count(a.id) as Count from ReporterTbl r left outer join AttachmentTbl a on r.id = a.id group by r.id (编辑:晋中站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |

